Situation: Joe, a DOH COVID-19 tracker, found out that the number of infected persons of COVID-19 in seven low-risk provinces of the country are 1, 9, 2, 12, 8, 7, and 10. Suppose that 5 provinces are drawn as sample.
1. What is the mean (u), variance (²) and standard deviation of the population (o)? 2. How many different samples of size n-5 can be drawn from the population?
List them with their corresponding mean. 3. Construct the sampling distribution of the sample mean.
4. What is the mean () of the sampling distribution of the sample mean? Compare this to the mean of the population.
5. What is the variance of the (o,) of the sampling distribution of the sample mean?
1
Expert's answer
2021-06-22T14:21:08-0400
1. We have population values 1,2,7,8,9,10,12 population size N=7 and sample size n=5.
Mean
μ=71+2+7+8+9+10+12=7
Variance
σ2=71((1−7)2+(2−7)2+(7−7)2
(8−7)2+(9−7)2+(10−7)2+(12−7)2)
=7100
Standard deviation
σ=σ2=7100≈3.779645
2. The number of possible samples which can be drawn without replacement is
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