Question #202273

Let X1,X2,.....,Xn be random sample of size n from a distribution with probability 

density function 

f(X; ,0)={ (θX) to the power (θ-1) ,0<X<1 , θ>0 Obtain a maximum likeyhood

0, elsewhere.

estimator of θ.


Expert's answer

f(X,θ)=θXθ−1,0≤X≤1,θ>0f(X,\theta)=\theta X^{\theta-1}, 0\le X\le1, \theta>0

L(θ)=∏i=1nf(X,θ)L(\theta)=\prod_{i=1}^nf(X,\theta)

=θn∏1n(Xi)θ−1=\theta ^n\prod_1^n(Xi)^{\theta-1}

ln⁡L(θ)=nln⁡θ+(θ−1)ln⁡∏1nXi\ln L(\theta)=n\ln\theta+(\theta-1)\ln \prod_1^n Xi

To maximize ln⁡L(θ)\ln L(\theta), we equate the first derivative of ln⁡L(θ)\ln L(\theta)to zero and solve for θ\theta

ddθln⁡L(θ)=nθ+ln⁡∏1nXi\frac{d}{d\theta}\ln L(\theta)=\frac{n}{\theta}+\ln \prod_1^n Xi

nθ+ln⁡∏1nXi=0\frac{n}{\theta}+\ln \prod_1^n Xi=0

nθ=−ln⁡∏1nXi\frac{n}{\theta}=-\ln \prod_1^n Xi

θ^=−n∏1nXi\hat{\theta}=-\frac{n}{\prod_1^nXi}


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