If a random variable u has t -distribution with n degree of freedom, find the
distribution of u2.
Solution:
Given, "u" has t-distribution.
So, "u\\sim \\dfrac{Z}{\\sqrt{X\/n}}=\\dfrac{N(0,1)}{\\chi^2_n\/n}"
Then, "u^2\\sim \\dfrac{Z^2}{{X\/n}}=\\dfrac{\\chi^2_1\/1}{\\chi^2_n\/n}=\\dfrac{n\\chi^2_1}{\\chi^2_n}"
Thus, distribution of "u^2" is "\\dfrac{n\\chi^2_1}{\\chi^2_n}"
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