10000 ‘Roshani’ light bulbs with a mean life of 150 days are installed in a new factory and their length of life is normally distributed with standard deviation of 10 days. How many Roshani-bulbs will expire in less than 160 days?
"P(X<160)=P(Z<\\frac{160-150}{10})=P(Z<1)=0.8413."
Number of Roshani-bulbs which will expire in less than 160 days:
"n=10000*0.8413=8413."
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