Question #197752

Number of students, mean and standard deviation of std X students of three different schools are as follows -

Govt Boys High School: N = 60, Mean = 38, SD = 5.2

Govt Girls High School: N = 50, Mean = 42, SD = 4.8

Govt Coeducation High School: N = 80, Mean = 46, SD = 6.1

I. Find how many students of Govt Boys High School are above the mean of Govt Girls High School

II. Find how many students of Govt Boys High School are above the mean of Govt Coeducation High School.

III. Find how many students of Govt Girls High School are above the mean of Govt Coeducation High School

IV. Find how many students of Govt Coeducation High School are below the mean of Govt Boys High School 


1
Expert's answer
2022-01-14T07:15:05-0500

I.

z=μ2μ1σ1=42385.2=0.77z=\frac{\mu_2-\mu_1}{\sigma_1}=\frac{42-38}{5.2}=0.77

P(z>0.77)=10.7794=0.2206P(z>0.77)=1-0.7794=0.2206

number of students of Govt Boys High School are above the mean of Govt Girls High School:

N1P(z>0.77)=600.2206=13N_1\cdot P(z>0.77)=60\cdot0.2206=13


II.

z=μ2μ1σ1=46385.2=1.54z=\frac{\mu_2-\mu_1}{\sigma_1}=\frac{46-38}{5.2}=1.54

P(z>1.54)=10.9382=0.0618P(z>1.54)=1-0.9382=0.0618

number of students of Govt Boys High School are above the mean of Govt Coeducation High School:

N1P(z>1.54)=600.0618=4N_1\cdot P(z>1.54)=60\cdot 0.0618=4


III.

z=μ2μ1σ1=46424.8=0.83z=\frac{\mu_2-\mu_1}{\sigma_1}=\frac{46-42}{4.8}=0.83

P(z>0.83)=10.7967=0.2033P(z>0.83)=1-0.7967=0.2033

number of students of Govt Girls High School are above the mean of Govt Coeducation High School:

N1P(z>0.83)=500.2033=10N_1\cdot P(z>0.83)=50\cdot 0.2033=10


IV.

z=μ2μ1σ1=38466.1=1.31z=\frac{\mu_2-\mu_1}{\sigma_1}=\frac{38-46}{6.1}=-1.31

P(z<1.31)=0.0951P(z<-1.31)=0.0951

number of students of Govt Coeducation High School are below the mean of Govt Boys High School:

N1P(z<1.31)=800.0951=8N_1\cdot P(z<-1.31)=80\cdot 0.0951=8


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