Question #197156

The following table is a frequency table of the scores obtained in a QTM quiz competition. Classes Frequency(f) 10 - 20 5 20 - 30 7 30 - 40 10 40 - 50 16 50 - 60 2 Total 40 Use the information in the table above and answer the following questions: 2.1 Find the mean [2] 2.2 Find the median [3] 2.3 Find modal score. [3] 2.4 Find the range of the scores. [1] 2.5 Find the variance of the scores. [4] 2.6 Find the standard deviation. [2] 2.7 Compute the coefficient of variation. [2] 2.8 Compute the interquartile range and the quartile deviation. 


1
Expert's answer
2021-05-25T15:54:32-0400



(1) Mean xˉ=xff=143040=35.75\bar{x} =\dfrac{\sum xf}{\sum f}=\dfrac{1430}{40}=35.75


(2) Median class corresponds to CF =N2=20= \dfrac{N}{2}=20

Median class =(30-40)

l=30,h=10,f=10,cf=22l=30,h=10, f=10,cf=22


M=l+(N2cff)×hM=30+202210×(10)M=302=28M=l+(\dfrac{\frac{N}{2}-cf}{f})\times h\\[9pt]M=30+\dfrac{20-22}{10}\times (10)\\[9pt]M=30-2=28


(3) Modal score-

M=l+(fof12fof1f2)hM=30+1072(10)167)×10M=3034(10)M=22.5M=l+(\dfrac{f_o-f_1}{2f_o-f_1-f_2})h\\[9pt]\Rightarrow M=30+\dfrac{10-7}{2(10)-16-7})\times 10\\[9pt]\Rightarrow M=30-\dfrac{3}{4}(10)\\[9pt]\Rightarrow M=22.5


(4) Range of score = Maximum value-minimum value=6010=50=60-10=50


(5) Variance of square σ2=(xxˉ)2n=1002.81340=25.07\sigma^2=\dfrac{(x-\bar{x})^2}{n}=\dfrac{1002.813}{40}=25.07


(6) Standard deviation =σ2=25.07=5=\sqrt{\sigma^2}=\sqrt{25.07}=5


(7) Coefficient of variation =σxˉ=535.75=0.14=\dfrac{\sigma}{\bar{x}}=\dfrac{5}{35.75}=0.14


(8) First quartile -

Q1=size of (40+1)5th term = size of 8.2th term =25Q_1=\text{size of }\dfrac{(40+1)}{5}^{th} \text{ term }= \text{ size of } 8.2^{th} \text{ term }=25


Q3= size of 3(40+1)5th term =size of 24.6thterm=45Q_3=\text{ size of } \dfrac{3(40+1)}{5}^{th} \text{ term } =\text{size of } 24.6^{th} term = 45


Inner Quartile Range =Q3Q1=4525=20= Q_3-Q_1=45-25=20


Quartile deviation =Q3Q12=45252=202=10\dfrac{Q_3-Q_1}{2}=\dfrac{45-25}{2}=\dfrac{20}{2}=10




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