Given numbers-- 1,2,3,4,5
(i) A=(1,2), B={1}
P(A)=52=0.4,P(B)=51=0.2,P(A∩B)=51=0.2
P(B∣A)=P(A)P(A∩B)=0.40.2=0.5>P(B)
Hence, P(B∣A)>P(B)
(ii) C=(1,2,3),D=(1,2,4)
P(D)=53=0.6,P(C)=53=0.6,P(C∩D)=52=0.4
P(D∣C)=P(C)P(D∩C)=0.60.4=0.66<P(D)
Hence, P(D∣C)<P(D) .
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