Question #197043

Consider the following ungrouped data:

41 46 7 46 32 5 14 28 48 49 8 49 48 25 41 8 22 46 40 48

Find the following:

a)  Arithmetic mean

b)  Geometric mean

c)  Harmonic mean

d)  Median

e)  Mode

f)  Range

g)  Mean deviation

h)  Variance

i)  Standard Deviation


Expert's answer

5,7,8,8,14,22,25,28,32,40,5, 7, 8, 8, 14, 22, 25, 28, 32, 40,

41,41,46,46,46,48,48,48,49,4941, 41, 46, 46, 46, 48, 48, 48, 49,49

a)

Arithmetic mean=∑i=120xi20=65120=32.55=\dfrac{\displaystyle\sum_{i=1}^{20}x_i}{20}=\dfrac{651}{20}=32.55


b)

Geometric mean=∏i=120xi20≈26.3908=\sqrt[20]{\displaystyle\prod_{i=1}^{20}x_i}\approx26.3908


c)

Harmonic mean=20∑i=1201xi≈18.8854=\dfrac{20}{\displaystyle\sum_{i=1}^{20}\dfrac{1}{x_i}}\approx18.8854

d)

Median = 40+412=40.5\dfrac{40+41}{2}=40.5


e)

Modes are 46 and 48. Each appeared 3 times


f) Range =49−5=44=49-5=44


g)  Mean deviation

Mean absolute deviation MADMAD


MAD=120∑i=120∣xi−xˉ∣=14.395MAD=\dfrac{1}{20}\displaystyle\sum_{i=1}^{20}|x_i-\bar{x}|=14.395

h)  Variance

The variance of a sample is:


s2=120−1∑i=120(xi−xˉ)2≈270.99736842s^2=\dfrac{1}{20-1}\displaystyle\sum_{i=1}^{20}(x_i-\bar{x})^2\approx 270.99736842

i)  Standard Deviation


s=s2≈270.99736842≈16.4620s=\sqrt{s^2}\approx\sqrt{270.99736842}\approx16.4620
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