1. In a box having 6 light switches, the probability of having a defective switch is 0.3 and the probability of having no defective switch is 0.6. Find the probability that there is at most 1 defective light switch in a box.
We have given that,
"n = 6"
"p = 0.3"
"q = 0.7"
We have to find the probability that there is at most 1 defective light switch in a box
Using the binomial distribution:
"P(X) = ^nC_r(p)^r(q)^{n-r}"
"P(X\\le 1) = P(X=0)+P(X=1)"
"= ^6C_0(0.3)^0(0.7)^2+ ^6C_1(0.3)^1(0.7)^1"
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