Given a standard normal distribution, find the area the curve between z=-1.97 and z=0.86.
We have to find the area between z=−1.97z = -1.97z=−1.97 and z=0.86z = 0.86z=0.86
i.e.P(−1.97<z<0.86)=0.8051−0.0244=0.7807i.e. \hspace{1mm} P(-1.97<z<0.86) = 0.8051-0.0244 = 0.7807i.e.P(−1.97<z<0.86)=0.8051−0.0244=0.7807
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