If a baseball player's batting average is 0.340 ( i.e., the probability of getting a hit each time at bat is 0.340), find the probability that the player will have a bad season and get at most 60 hits in 200 times at bat?
We have given that,
"n = 200"
"p = 0.34"
"x=" number of hits
"n=" total times at bat
We know,
"\\mu = np = 200 \\times 0.34 = 68"
"\\sigma = \\sqrt{npq} = \\sqrt{200 \\times 0.34 \\times 0.66} = 6.6993"
Applying continuity correction,
"z = \\dfrac{x-\\mu}{\\sigma}"
"z = \\dfrac{60-68}{6.6993} = -1.12"
For the normal standard distribution,
"P(z < - 1.12) = 13.14% = 13.1" %
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