Question #190464

If a baseball player's batting average is 0.340 ( i.e., the probability of getting a hit each time at bat is 0.340), find the probability that the player will have a bad season and get at most 60 hits in 200 times at bat?


1
Expert's answer
2021-05-07T14:32:24-0400

We have given that,

n=200n = 200

p=0.34p = 0.34

x=x= number of hits

n=n= total times at bat

We know,


μ=np=200×0.34=68\mu = np = 200 \times 0.34 = 68


σ=npq=200×0.34×0.66=6.6993\sigma = \sqrt{npq} = \sqrt{200 \times 0.34 \times 0.66} = 6.6993


Applying continuity correction,


z=xμσz = \dfrac{x-\mu}{\sigma}


z=60686.6993=1.12z = \dfrac{60-68}{6.6993} = -1.12


For the normal standard distribution,


P(z<1.12)=13.14P(z < - 1.12) = 13.14% = 13.1 %


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
10.05.21, 12:11

Dear Mayah, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!

Mayah
08.05.21, 00:58

Thank you, it's helps me so much

LATEST TUTORIALS
APPROVED BY CLIENTS