For a certain binary communication channel, the probability a transmitted ‘0’ bit is received as a ‘0’ bit is 0.95 and for ‘1’ bit, it is 0.90. The probability that ‘0’ bit is transmitted is 0.4, Find
a. Probability that ‘1’ bit is received.
Let "A" be the event of transmitting '1' and "\\bar{A}" be the event of transmitting '0'.
and "B" be the event of receiving '1" and "\\bar{B}" be the event of receiving '0'.
a. Probability that ‘1’ bit is received-
"P(B)=P(A)P(\\dfrac{B}{A})+P(\\bar{A})P(\\dfrac{B}{\\bar{A}})"
"= 0.9\\times (1-0.4)+0.4\\times (1-0.95)\\\\[9pt]=0.6\\times 0.9+0.4\\times 0.05=0.56"
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