If x has the probability function 𝑓(𝑥) = 𝑘/2^x for x=0,1,2,……… then determine the followings
a) Vale of k
b) P(x≥ 4)
By definition,
"\\displaystyle \\sum_{x=0}^\\infty \\frac{k}{2^x} = 1 = k\\sum_{x=0}^\\infty \\frac{1}{2^x} = k \\cdot 2"
"k=1\/2"
"\\displaystyle P(X \\geq 4) = 1 - P(X < 4) = 1 - \\frac{1}{2}\\sum_{x=0}^3 \\frac{1}{2^x}= 1 - \\frac{1}{2} \\cdot \\frac{15}{8} = 1 - \\frac{15}{16} = \\frac{1}{16}"
Answer: "k=1\/2; P(X\\geq 4) = 1\/16."
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