A bag contains 6 white and 9 black balls . Four balls are drawn at a time .Find the probability for the first draw to give four white and second draw to give four black balls in each of the following cases:
a) The balls are replaced before the second draw.
b) The balls are not replaced before the second draw
Two draws are independent events, so the probabilities of the individual draws will multiply.
a) "\\displaystyle P(A) = \\frac{C(6,4)}{C(15,4)} \\cdot \\frac{C(9,4)}{C(15,4)} = \\frac{15}{1365} \\cdot \\frac{126}{1365} =0.0010 = 0.1\\%"
b) "\\displaystyle P(B) = \\frac{C(6,4)}{C(15,4)} \\cdot \\frac{C(9,4)}{C(11,4)} = \\frac{15}{1365} \\cdot \\frac{126}{330} =0.0042 = 0.42\\%"
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