A student organization lists as its members 2 freshmen, 3 sophomores, 5 juniors, and 2 seniors. If a team of 4 is to be selected at random, find the probability that all year levels are represented.
There are 12 people in total. The number of combinations we can choose 4 members out of 12 (without any constraints) is
"C(12, 4) = \\begin{pmatrix}\n 12 \\\\ 4\n\\end{pmatrix} = 495"
Then among these 4 members, we need to have 1 freshman, 1 sophomore, 1 junior, and 1 senior.. This can be done in
"\\begin{pmatrix}\n 2 \\\\ 1\n\\end{pmatrix} \\cdot \\begin{pmatrix}\n 3 \\\\ 1\n\\end{pmatrix} \\cdot \\begin{pmatrix}\n 5 \\\\ 1\n\\end{pmatrix} \\cdot \\begin{pmatrix}\n 2 \\\\ 1\n\\end{pmatrix} = 2 \\cdot 3 \\cdot 5 \\cdot 2 =60"
The probability is
"\\displaystyle P(A) = \\frac{60}{495} = 0.12 =12\\%"
Answer: 0.12
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