Question #183093

It is thought that the proportion of defective items produced by a particular machine is 10%. A random sample of 100 items is inspected and found to contain 15 defective items.

(a) State the sample proportion in this test.

(b) Compute its statistical value


Expert's answer

a) the sample proportion

p^=xn\hat p=\frac x n

where x is the number of defective items and n is the sample size.

p^=15100\hat p=\frac{15}{100}

=0.15

b) statistical value

we wish to test the hypotheses;

H0:p=0.1

H1:p≠ 0.1

np>5;nq>5np>5; nq>5 implies that the proportions follow a normal distribution.

we create a 95% confidence interval to test the claim.

C.I=p^±z(p^)(1p^)nC.I=\hat p ±z*\sqrt{\frac{(\hat p)(1-\hat p)}{n}}

=0.15±1.960.150.851000.15±1.96*\sqrt{\frac{0.15*0.85}{100}}

=(0.08,0.22)

The population proportion(0.1) is within the 95% confidence interval. we are 95% confident that the proportion of defective items produced by a particular machine is 10%.


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