Question #183093

It is thought that the proportion of defective items produced by a particular machine is 10%. A random sample of 100 items is inspected and found to contain 15 defective items.

(a) State the sample proportion in this test.

(b) Compute its statistical value


1
Expert's answer
2021-05-03T08:32:58-0400

a) the sample proportion

p^=xn\hat p=\frac x n

where x is the number of defective items and n is the sample size.

p^=15100\hat p=\frac{15}{100}

=0.15

b) statistical value

we wish to test the hypotheses;

H0:p=0.1

H1:p≠ 0.1

np>5;nq>5np>5; nq>5 implies that the proportions follow a normal distribution.

we create a 95% confidence interval to test the claim.

C.I=p^±z(p^)(1p^)nC.I=\hat p ±z*\sqrt{\frac{(\hat p)(1-\hat p)}{n}}

=0.15±1.960.150.851000.15±1.96*\sqrt{\frac{0.15*0.85}{100}}

=(0.08,0.22)

The population proportion(0.1) is within the 95% confidence interval. we are 95% confident that the proportion of defective items produced by a particular machine is 10%.


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