Answer to Question #183112 in Statistics and Probability for Kyle

Question

 A fishbowl contains 3 green balls, 2 blue balls, and 4 red balls. In a random sample of 5 balls, find the probability that both blue balls and at least 1 red ball are selected. 

Answer 1

Total balls = 3 green + 2 blue + 4 red

Total balls = 9

Given that 5 balls are drawn$\implies$9C5

2 blue balls should be drawn = 2C2

1 red ball should be drawn = 4C1

2 green balls should be drawn = 3C2

The probability of selecting both blue balls and at least 1 red ball would be:

Total probability = (2C2 + 4C1 + 3C2) / 9C5

= 7 / 126

= 0.055 or 5.5%