Question #175796

Ten android tablets will be delivered to a certain school for testing but three of them are defective tablet, Y represent the nondefective tablet and L represent the random variable representing the defective tablet will occur. Complete the table below and find the values of random variable L.


Expert's answer

Possible Values of the OutcomesRandom Variable LLL2LY1YL1YY0\def\arraystretch{1.5} \begin{array}{c:c} \text{Possible } & \text{Values of the } \\ \text{Outcomes} & \text{Random Variable} \ L\\ \hline LL & 2 \\ LY & 1 \\ YL & 1\\ YY & 0 \end{array}

P(L=0)=(30)(10320)(102)=2145=715P(L=0)=\dfrac{\dbinom{3}{0}\dbinom{10-3}{2-0}}{\dbinom{10}{2}}=\dfrac{21}{45}=\dfrac{7}{15}

P(L=1)=(31)(10321)(102)=2145=715P(L=1)=\dfrac{\dbinom{3}{1}\dbinom{10-3}{2-1}}{\dbinom{10}{2}}=\dfrac{21}{45}=\dfrac{7}{15}

P(L=2)=(32)(10322)(102)=345=115P(L=2)=\dfrac{\dbinom{3}{2}\dbinom{10-3}{2-2}}{\dbinom{10}{2}}=\dfrac{3}{45}=\dfrac{1}{15}

l012P(L=l)715715115\def\arraystretch{1.5} \begin{array}{c:c} l & 0 & 1 & 2 \\ \hdashline \\ P(L=l) & \dfrac{7}{15} & \dfrac{7}{15} & \dfrac{1}{15} \end{array}



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