Answer to Question #175773 in Statistics and Probability for Denisse Bisuña

Question #175773

1.Who knows the game sipa? A Physical Education major sought to determine whether all Filipinos are familiar with this game. Among 1,500 respondents, 358 knew the game. Use 95% confidence to estimate the population proportion p and q. Interpret the sample data.

A. Find (za/2)2 given each of the following:

-----------

E


a. With 90% confidence, E = 0.01.

b. With 90% confidence, E = 0.02.

c. With 95% confidence, E = 0.15.

d. With 95% confidence, E = 0.08

e. With 99% confidence, E = 0.05.





1
Expert's answer
2021-04-13T12:23:00-0400

1.

E=Zα/2p(1p)nE=Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}}

n=1500,p=358/1500=0.2387=23.87%, q=76.13%n=1500,p=358/1500=0.2387=23.87\%,\ q=76.13\%

E=1.960.23870.76131500=0.0216=2.16%E=1.96\sqrt{\frac{0.2387\cdot0.7613}{1500}}=0.0216=2.16\%

The population proportion p and q are in 95% confidence interval with error 2.16%


A. a)

(Zα/2)2=(1.65±0.01)2(Z_{\alpha/2})^2=(1.65\pm0.01)^2

2.69(Zα/2)22.762.69\leq (Z_{\alpha/2})^2\leq 2.76


b)

(Zα/2)2=(1.65±0.02)2(Z_{\alpha/2})^2=(1.65\pm0.02)^2

2.66(Zα/2)22.792.66\leq (Z_{\alpha/2})^2\leq 2.79


c)

(Zα/2)2=(1.96±0.15)2(Z_{\alpha/2})^2=(1.96\pm0.15)^2

3.28(Zα/2)24.453.28\leq (Z_{\alpha/2})^2\leq 4.45


d)

(Zα/2)2=(1.96±0.08)2(Z_{\alpha/2})^2=(1.96\pm0.08)^2

3.53(Zα/2)24.163.53\leq (Z_{\alpha/2})^2\leq 4.16


e)

(Zα/2)2=(2.58±0.05)2(Z_{\alpha/2})^2=(2.58\pm0.05)^2

6.40(Zα/2)26.926.40\leq (Z_{\alpha/2})^2\leq 6.92

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