Samples of size 3 without replacement:
{5,7,9}; {5,7,11}; {5,7,13}; {5,9,11};{5,9,13}; {5,11,13}; {7,9,11}; {7,9,13}; {7,11,13}; {9,11,13}
If A is odd number verily the biasedness property of sample variance S2.
Sn2=n(n−1)1∑i=j2(Xi−Xj)2=n(n−1)1((n−1)∑i=1nXi2−∑i=jXiXj)
The expectation of sample variance:
E[Sn2]=n∑i=1nE[Xi2]−n(n−1)∑i=jE[Xi∗Xj]
Since we have independent variables:
E[XiXj]=E[Xi]∗E[Xj]
Let assume that:
E[Xi2]=μ2 and E[Xi]=μ1
Then:
∑i=1nE[Xi2]=n∗μ2 and ∑i=jE[Xi]E[Xj]=n(n−1)μ12
Finally:
E[Sn2]=μ2−μ12=Var[X]
So, S2 is unbiased.
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