Answer to Question #152782 in Statistics and Probability for izah

Question #152782
1. An operator trainee is attempting to monitor a filling process that has an overall average of 650 cc. The average range is 22 cc. If you use a sample size of 8, what are the upper and lower control limits for the x-bar chart and R-chart?

A2 = 0.373, D4 = 1.864, D3 = 0.136

2. A small, independent amusement park collects data on the number of cars with out-of-state license plates. The sample size is fixed at n=100 each day. Data from the previous 10 days indicate the following number of out-of-state license plates:

Day Out-of-state Plates
1 6
2 4
3 5
4 7
5 8
6 3
7 4
8 15
9 3
10 11

(a) Calculate the overall proportion of "tourists" (cars with out-of-state plates) and the standard deviation of proportions.
(b) Using ±3σ limits, calculate the LCL and UCL for these data.
(c) Is the process under control? Explain.
1
Expert's answer
2020-12-25T15:24:51-0500

1. Xbar = 650 cc

Rbar = 22 cc

Sample size n=8

A2=0.373 (for n=8)

D3=0.136 (for n=8)

D4=1.864 (for n=8)

Control limits for 3 Sigma Xbar Chart

"UCL_x = Xbar + A_2 \\times Rbar = 650 + 0.373 \\times 22 = 650+8.206 \\\\\n\nUCL_x = 658.206 \\\\\n\nLCL_x = Xbar - A_2 \\times Rbar = 650 - 0.373 \\times 22 = 650 - 8.206 \\\\\n\nUCL_x = 641.794"

Control limits for 3 Sigma R Chart

"UCLR = D_4 \\times Rbar = 1.864 \\times 22 =41.008 \\\\\n\nUCLR =41.008 \\\\\n\nLCLR = D_3 \\times Rbar = 0.136 \\times 22 = 2.992 \\\\\n\nLCLR = 2.992"

2.

(a) The overall proportion of "tourists":

"P = \\frac{0.06+0.04+0.05+0.07+0.08+0.03+0.04+0.15+0.03+0.11}{10} = 0.066"

Standard deviation of proportions:

"\u03c3 = \\sqrt{\\frac{0.066 \\times (1-0.066)}{100}} = 0.0248"

(b)

"LCL = P - 3\u03c3 \\\\\n\nLCL = 0.066 -3 \\times 0.0248 = 0 \\\\\n\nUCL = P + 3\u03c3 \\\\\n\nUCL = 0.066 + 3 \\times 0.0248 = 0.1404"

(c) The process is under control because the proportion of tourists who drive car with out of state plates is within the upper and lower control limits.


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