Question

Find the area under the normal curve between a. z = -1.22 and z = 2.32 b. z =1.27 and z= 1.77, c. z =2.0 and z = -0.50. 

Answer 1

a.

$$P(-1.22<Z<2.32)=P(Z<2.32)-P(Z\leq-1.22)$$

$$\approx0.98982956-0.11123244\approx0.8786$$

$0.8786$

b.

$$P(1.27<Z<1.77)=P(Z<1.77)-P(Z\leq1.27)$$

$$\approx0.96163643-0.89795768\approx0.0637$$

$0.0637$

c.

$$P(-0.50<Z<2.0)=P(Z<2.0)-P(Z\leq-0.50)$$

$$\approx0.97724987-0.30853754\approx0.6687$$

$0.6687$