A) "\\int^1_{-1}f(x)dx=1"
"\\int^1_{-1}k(3-x^2)dx=(3kx-kx^3\/3)|_{-1}^1=3k-k\/3+3k-k\/3=6k-2k\/3=18k\/3-2k\/3=16k\/3=1"
k=3/16
B)"\\int_0^1( 3(3-x^2)\/16) dx=(9x\/16-x^3\/16)|_0^1=9\/16-1\/16=8\/16=1\/2"
C)"\\int_{-1\/2}^{1\/2}(3 (3-x^2)\/16) dx=(9x\/16-x^3\/16)|_{-1\/2}^{1\/2}=9\/32-1\/128+9\/32-1\/128=18\/32-2\/128=9\/16-1\/64=36\/64-1\/64=35\/64"
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