X∼N(aX,sX2)
Given aX=4000m,sX=1000m
A first person and a second person will be right when cloud height will fall in the set A∩B ={2000m < X< 3300m)
P(2000<X<3300)=
=P(Z<10003300−4000)−P(Z≤10002000−4000)=
=P(Z<−0.7)−P(Z−≤2)≈
≈0.24196365−0.02275013≈0.2192 If A first person and a second person will be right then and a third person will be right
The probability that each person will win the bet is 0.2192.
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