"X\\sim N(a_X, s_X^2 )"
Given "a_X=4000 m, s_X=1000m"
A first person and a second person will be right when cloud height will fall in the set "A\\cap B" ={2000m < X< 3300m)
"=P(Z<\\dfrac{3300-4000}{1000})-P(Z\\leq\\dfrac{2000-4000}{1000})="
"=P(Z<-0.7)-P(Z-\\leq2)\\approx"
"\\approx0.24196365-0.02275013\\approx0.2192"
If A first person and a second person will be right then and a third person will be right
The probability that each person will win the bet is "0.2192".
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