Class has 100 students.
Probability to pick up French is P(B)=60100=0.6\displaystyle P(B) =\frac{60}{100}= 0.6P(B)=10060=0.6 .
Probability to pick up female French is P(A∩B)=10100=0.1\displaystyle P(A\cap B) = \frac{10}{100} = 0.1P(A∩B)=10010=0.1.
P(A∣B)=P(A∩B)P(B)=0.10.6=16\displaystyle P(A|B) = \frac{P(A\cap B)}{P(B)} = \frac{0.1}{0.6}= \frac{1}{6}P(A∣B)=P(B)P(A∩B)=0.60.1=61
Answer: 1/6.
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