Question

What is the probability that the total of two dice will be greater than 8, given
that the first die is a 6?

Answer 1

The first die is already 6, so to satisfy the condition that sum is greater than 8, the second die must be {3,4,5,6}. We have 4 events that satisfy the condition, and 6 possible events (getting any number from 1 to 6). So the probability is

$\displaystyle P(A) = \frac{4}{6} = \frac{2}{3}$

Answer: 2/3