Given that there are in all 3 engineers, 4 economist, 2 statistician and 1 chartered accountant.
Total number of samples n = 10
r = number of random selection
The probability 'P' that the committee of 4 team members consists of one chartered accountant and at least one economist is given by the following sets of possibilities -
Based on various combinations for selection from individual groups we get,
P = "\\frac {Total\\ no\\ of\\ favorable\\ outcomes\\ in\\ various\\ combinations}{Total\\ number \\ of\\ outcomes}"
P = { {1C1x4C1x3C1x2C1} + {1C1x4C1x3C2x2C0} + {1C1x4C1x3C0x2C2} + {1C1x4C2x3C1x2C0} + {1C1x4C2x3C0x2C1} + {1C1x4C3x3C0x2C0} } / 10C4
By using the formula for combination nCr = "\\frac {n!}{r!(n-r)!}"
Substituting the value of probabilities in the above equation we get,
P = 0.35238
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