Let X = the random variable denoting the number of pages in the PDF document that has been created
Then we have,
X ~ Uniform{a, b}, a and b are the parameters of the distribution
Now, the expectation and variance of X are given by,
E(X) = "\\frac{a+b}{2}"
and Var(X) = "\\frac{(b-a+1)^2-1}{12}"
Here we are given,
a = 5, b = 9
Using these values we get,
E(X) = "\\frac{5+9}{2}=7"
and Var(X) = "\\frac{(9-5+1)^2-1}{12}=2"
Then standard deviation of X = "\\sqrt{Var(X)}=\\sqrt{2}=1.414" (rounded to 3 decimal places)
Answer: The mean and standard deviation of the number of pages in the document are 7 and 1.414 respectively.
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