Given : n= 15
p=0.25
since the conditions the experiment consists of n identical trials. Each trial results in one of the two outcomes, called success and failure. The probability of success, denoted p, remains the same from trial to trial, we use binomial distribution here.
a)
P("3\\leq x\\leq 6)" =P(3)+P(4)+P(5)+P(6)
=0.2252+0.2252+0.1651+0.0917
= 0.7073
b) P(x<4)= P(x=0)+P(x=1)+P(X=2)+P(X=3)
=0.0134+0.0668+0.1559+0.2252
= 0.4613
c)P(X>5)= 1- P(X<=5)
=1- [P(x=0)+P(x=1)+p(X=2)+P(x=3)+P(x=4)+P(x=5)]
= 1-0.0134+0.0668+0.1559+0.2252+0.2252+0.1651
=1- 0.8516
=0.1484
d)mean= np=15*0.25=3.75
sd= "\\sqrt{(n*p*(1-p))}" ="\\sqrt{(15*0.25*(1-0.25))}" =1.677
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