i)
Where p is represents is planned to visit, NP not planned to visit, v is visited and NV is not visited.
ii) Find the probability of selecting a respondent who actually visited GH HOTEL.
P(v)= p(p and v) +p(Np and v)
P(v) = (0.3*0.67) + (0.7*0.07)
P(v)=0.25
This could also be interpreted as the number of those who visited divided by the total number of respondents. Which is p(v) =250/1000 = 0.25
iii) Find the probability of panned visit or actual visit
P(p or v) = p(p) + p(Np and v)
P(p or v) = 0.3 + (0.7*0.07)
P(p or V) = 0.349 = 0.35
This could also be the total number of those who planned to go for a visit added together with the number of those who didn’t plan to go for a visit but went.
P( p or v) = (300+50)/1000= 0.35
iv)
P(v)= p(p and v) +p(Np and v)
P(v) = (0.3*0.67) + (0.7*0.07)
P(v)=0.25
This could also be interpreted as the number of those who visited divided by the total number of respondents. Which is p(v) =250/1000 = 0.25
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