X=Number of miles that Anita's motorbike will be travel on one gallon of petrol
Standard normal distribution is obtain by using,
"z=\\frac{x-\\bar{x}}{\\sigma}=\\frac{x-135}{12}\\\\"
12)a)
i)
"P(X>111)=P(Z>\\frac{111-135}{12})\\\\\nP(X>111)=P(Z>-2)\\\\\nP(X>111)=0.9772\\\\"
Probability that, without refeulling,she can travel more than 111 miles=0.9772
ii)
"P(141<X<150)=P(\\frac{141-135}{12}<Z<\\frac{150-135}{12})\\\\\nP(141<X<150)=P(0.5<Z<1.25)\\\\\nP(141<X<150)=P(0<Z<1.25)\\\\\n\\hspace{12 em}-P(0<Z<0.5)\\\\\nP(141<X<150)=0.3944-0.1915\\\\\nP(141<X<150)=0.2029\\\\"
Probability that, without refeulling,she can travel between 141 and 150 miles=0.2029
b)task is to find z such that,
"P(Z<z)=0.9\\\\\nz=1.282\\\\\nz=\\frac{x-135}{12}\\\\\n1.282=\\frac{x-135}{12}\\\\\nx=150.384"
longest journey that Anita can undertake,if she is to have a probability of that at least 0.9 of completing it on one gallon of petrol is 150.384 miles
Comments
Leave a comment