let X=The life of a compressor manufactured by a company
μ=200monthsλ=μ1=2001=0.005
here X∼exp(0.005)
f(x)={0.005e(−0.005x)0if x≥0if x<0
and
F(x)={1−e(−0.005x)0if x≥0if x<0
i)
P(X<200)=F(200)P(X<200)=1−e(−0.005∗200)P(X<200)=0.6321
probability that the life of a compressor is less than 200 months=0.6321
ii)
P(100<X<300)=F(300)−F(100)P(100<X<300)=(1−e(−0.005∗300))−(1−e(−0.005∗100))P(100<X<300)=0.3834
probability that the life of a compressor is between 100 months to 25 years=0.3834
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