Question #110909
The life of a compressor manufactured by a company is known to be 200 months on an
average following an exponential distribution .Find the probability that the life of a
compressor is i) less than 200 months ii) between 100 months to 25 years.
1
Expert's answer
2020-04-21T14:41:40-0400

let X=The life of a compressor manufactured by a company 

μ=200monthsλ=1μ=1200=0.005\mu=200months\\ \lambda=\frac{1}{\mu}=\frac{1}{200}=0.005

here Xexp(0.005)X\thicksim exp(0.005)

f(x)={0.005e(0.005x)if x00if x<0f(x)= \begin{cases} 0.005e^{(-0.005x)} &\text{if } x\ge0 \\ 0 &\text{if } x<0 \end{cases}


and


F(x)={1e(0.005x)if x00if x<0F(x)= \begin{cases} 1-e^{(-0.005x)} &\text{if } x\ge0 \\ 0 &\text{if } x<0 \end{cases}


i)

P(X<200)=F(200)P(X<200)=1e(0.005200)P(X<200)=0.6321P(X<200)=F(200)\\ P(X<200)=1-e^{(-0.005*200)}\\ P(X<200)=0.6321

probability that the life of a compressor is less than 200 months=0.6321

ii)

P(100<X<300)=F(300)F(100)P(100<X<300)=(1e(0.005300))(1e(0.005100))P(100<X<300)=0.3834P(100<X<300)=F(300)-F(100)\\ P(100<X<300)=(1-e^{(-0.005*300)})\\ \hspace{12 em}-(1-e^{(-0.005*100)})\\ P(100<X<300)=0.3834

probability that the life of a compressor is between 100 months to 25 years=0.3834



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