Exponential Distribution Probability
F(x;λ)={01−e−λxif x<0if x≥0 Given β=200,λ=β1=2001
i) less than 200 months
P(X<200)=F(200;λ)=1−e−2001(200)=
=1−e−1≈0.63212 ii) between 100 months to 25 years.
P(100<X<3000)=F(3000;λ)−F(100;λ)=
=1−e−2001(3000)−(1−e−2001(100))=
=e−21−e−15≈0.60653066−0.00000031≈0.60653
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