The number of emitted particles has Poisson distribution.
"P\\{\\xi=k\\}=\\frac{\\lambda^k}{k!}e^{-\\lambda}, k=0,1,\\ldots"
We have "\\lambda_1=10, \\lambda_2=17."
We will take samples of sizes "n_1=20, n_2=20" from the first and the second populations.
"P\\{\\xi=20\\}=\\frac{10^{20}}{20!}e^{-10}\\approx 0.0019.\\\\\nP\\{\\xi=20\\}=\\frac{17^{20}}{20!}e^{-17}\\approx 0.0692."
We get relative frequencies:
"\\omega_1=0.0019\\\\\n\\omega_2=0.0692"
"H_0: p_1=p_2; H_1: p_1\\neq p_2\\\\\n\\text{where } p_i \\text{ is probability that event A (the particle emits)}\\\\\n\\text{will happen in the i-th population}."
We will use the following random variable:
"u=\\frac{\\omega_1-\\omega_2}{\\sqrt{(\\omega_1+\\omega_2)(1-(\\omega_1+\\omega_2))(\\frac{1}{n_1}+\\frac{1}{n_2}})}\\\\\nu_{obs}\\approx -0.8281\\\\\n\\Phi(u_{cr})=\\frac{1-\\alpha}{2}=0.475\\\\\nu_{cr}=1.96\\\\\n(-\\infty,-1.96)\\cup (1.96,\\infty)\\text{ --- critical region}.\\\\\nu_{obs}\\text{ does not fall into the critical region. So we accept } H_0."
The rate of emission did not change after an experimental treatment.
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