Question #110543

What is the probability of finding a middle manager with a weekly income of

between K840 and K900?

(ii) What is the percent of middle managers that earn more than K905?

(iii) What is the percent of middle managers that earn less than K905?

(iv) What is the probability of finding a middle manager with weekly income of

between K750 and K850?

(v) What is the probability of finding a middle manager with a weekly income of

between K700 and K790?

(vi) Above what income would the top 10% of the managers earn?

(vii) Below what income would the lowest 10% of the managers earn?

Expert's answer

Let X=X= the weekly income: XN(μ,σ2)X\sim N(\mu, \sigma^2)

Given that μ=800,σ=85.\mu=800, \sigma=85.


Z=XμσN(0,1)Z={X-\mu \over \sigma}\sim N(0,1)

(i) The probability of finding a middle manager with a weekly income of between K840 and K900 is


P(840<X<900)=P(X<900)P(X840)=P(840<X<900)=P(X<900)-P(X\leq840)==P(Z<90080085)P(X84080085)=P(Z<{900-800 \over85})-P(X\leq{840-800 \over85})\approxP(Z<1.176471)P(X0.470588)\approx P(Z<1.176471)-P(X\leq0.470588)\approx

(ii) The percent of middle managers that earn more than K905 is 


P(X>905)=1P(X905)=P(X>905)=1-P(X\leq905)==1P(Z90580085)1P(Z1.23529)=1-P(Z\leq{905-800 \over85})\approx1-P(Z\leq1.23529)\approx10.891640.108410.84%\approx1-0.89164\approx0.1084\approx10.84\%

(iii) The percent of middle managers that earn less than K905 is  


P(X<905)=P(Z<1.23529)P(X<905)=P(Z<1.23529)\approx0.8916489.16%\approx0.89164\approx89.16\%

(iv) The probability of finding a middle manager with weekly income of between K750 and K850 is


P(750<X<850)=P(X<850)P(X750)=P(750<X<850)=P(X<850)-P(X\leq750)==P(Z<85080085)P(X75080085)=P(Z<{850-800 \over85})-P(X\leq{750-800 \over85})\approxP(Z<0.588235)P(X0.588235)\approx P(Z<0.588235)-P(X\leq-0.588235)\approx0.721810.278190.443644.36%\approx0.72181-0.27819\approx0.4436\approx44.36\%

(v) The probability of finding a middle manager with a weekly income of between K700 and K790 is


P(700<X<790)=P(X<790)P(X700)=P(700<X<790)=P(X<790)-P(X\leq700)==P(Z<79080085)P(X70080085)=P(Z<{790-800 \over85})-P(X\leq{700-800 \over85})\approxP(Z<0.117647)P(X1.176471)\approx P(Z<-0.117647)-P(X\leq-1.176471)\approx0.453170.119700.3335\approx0.45317-0.11970\approx0.3335

vi) Above what income would the top 10% of the managers earn?  


P(Z>z)=0.1P(Z>z^*)=0.1

z=x800851.28155z^*={x^*-800 \over 85}\approx1.28155

x909x^*\approx909

(vii) Below what income would the lowest 10% of the managers earn?


P(Z<z)=0.1P(Z<z^*)=0.1

z=x800851.28155z^*={x^*-800 \over 85}\approx-1.28155

x691x^*\approx691


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