Question #108909
the coffee machine in the pi cafe has three dispensers p,q, and r. the probabilities that each malfunctions on a given day are 0.007,0.003 and 0.001 respectively.find the probability that exact one of the dispensers malfunctions on a given day.
1
Expert's answer
2020-04-13T11:01:21-0400

From the given data probability of malfunction is given by,

P(p)=0.007P(q)=0.003P(r)=0.001P(p)=0.007\\ P(q)=0.003\\ P(r)=0.001\\

And for each of the machines , probability of not malfunctioning is given by,

P(p)=10.007=0.993P(q)=10.003=0.997P(r)=10.001=0.999P'(p)=1-0.007=0.993\\ P'(q)=1-0.003=0.997\\ P'(r)=1-0.001=0.999\\


Since malfunctions are independent,

Probability that exact one of the dispensers malfunctions is given by,


P(E)=P(p)P(q)P(r)+P(p)P(q)P(r)+P(p)P(q)P(r)P(E)=0.993×0.997×0.001+0.993×0.003×0.999+0.007×0.997×0.999P(E)=0.00099+0.00297+0.00697P(E)=0.0109P(E)=P'(p)P'(q)P(r)+P'(p)P(q)P'(r)+P(p)P'(q)P'(r)\\ P(E)=0.993\times0.997\times0.001+0.993\times0.003\times0.999+0.007\times0.997\times0.999\\ P(E)=0.00099+0.00297+0.00697\\ P(E)=0.0109




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