The probability of production is given by,
"P(A) = 0.6,\\\\\nP(B) = 0.3,\\\\\nP(C) = 0.1."
Part "X" made by each machine is given by,
"P(X | A) = 0.4,\\\\\nP( X | B) = 0.5,\\\\\nP(X | C ) = 0.7."
Probability of producing part "X"
"P(X) = P(X | A) P(A) + P(X | B) P(B) + P(X | C) P(C)\\\\"
Substituting from above values gives,
"P(X)= 0.46"
From
"P(X | A) P(A) = P(A | X) P(X) \\to\n\nP(A | X) = P(X | A) P(A) \/ P(X),"
"P(A | X) = 0.521"
Answer: "P(A | X) = 0.521"
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