The probability of production is given by,
P(A)=0.6,P(B)=0.3,P(C)=0.1.
Part "X" made by each machine is given by,
P(X∣A)=0.4,P(X∣B)=0.5,P(X∣C)=0.7.
Probability of producing part "X"
P(X)=P(X∣A)P(A)+P(X∣B)P(B)+P(X∣C)P(C)
Substituting from above values gives,
P(X)=0.46
From
P(X∣A)P(A)=P(A∣X)P(X)→P(A∣X)=P(X∣A)P(A)/P(X),
P(A∣X)=0.521
Answer: P(A∣X)=0.521
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