Answer to Question #108848 in Statistics and Probability for Dhruv patel

Question #108848
machine A,B and C all produce the same two parts X and Y.of all the parts produced,machine A produces 60% ,machine B produced 30% and machine C produced 10% in addition,40% of the same parts made by machine A are part X,50% of the parts made by machine B are part X,70% of the parts made by machine C are part X,A part produced by this company is randomly sample and is determined to be an X part. What is the probability that the part came from machine A.
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Expert's answer
2020-04-10T12:49:02-0400

The probability of production is given by,

P(A)=0.6,P(B)=0.3,P(C)=0.1.P(A) = 0.6,\\ P(B) = 0.3,\\ P(C) = 0.1.


Part "X" made by each machine is given by,

P(XA)=0.4,P(XB)=0.5,P(XC)=0.7.P(X | A) = 0.4,\\ P( X | B) = 0.5,\\ P(X | C ) = 0.7.


Probability of producing part "X"

P(X)=P(XA)P(A)+P(XB)P(B)+P(XC)P(C)P(X) = P(X | A) P(A) + P(X | B) P(B) + P(X | C) P(C)\\

Substituting from above values gives,

P(X)=0.46P(X)= 0.46


From

P(XA)P(A)=P(AX)P(X)P(AX)=P(XA)P(A)/P(X),P(X | A) P(A) = P(A | X) P(X) \to P(A | X) = P(X | A) P(A) / P(X),


P(AX)=0.521P(A | X) = 0.521

Answer: P(AX)=0.521P(A | X) = 0.521


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