Let there be n students taking the exam, and each of them obtained x1,x2,...xnx_1, x_2, ...x_nx1,x2,...xn marks in the exam.
Then the average score on the exam is given by
μ=(x1+x2+...xn)/n\mu=(x_1+x_2+...x_n)/nμ=(x1+x2+...xn)/n
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