i) Let random variale "\\xi" is the number of women arrived at the health centre during a 5-minute period. Then "\\xi\\in" Poisson ("\\lambda") where "\\lambda=5(0.3)=1.5".
We will find "P\\{\\xi=0\\}, P\\{\\xi=1\\}, P\\{\\xi=2\\}" and calculate sum of these probabilities.
Using cumulative table we get "0.8088." Then our probability is "1-0.8088=0.1912."
ii) Let random variable "\\eta" is the number of men arrived at the health centre during a 5-minute period. Then "\\eta\\in" Poisson ("\\lambda") where "\\lambda=5(0.2)=1."
We will find "P\\{\\xi=0\\}, P\\{\\xi=1\\}" and calculate sum of these probabilities.
Using cumulative table we get "0.7358". Then probability that at least 2 men arrive at the health centre during a 5-minute period is "1-0.7358=0.2642."
Then our probability is "(0.2642)(0.1912)\\approx 0.05" (events are independent).
Comments
Leave a comment