a) Probability that the student answers a question incorrectly is "\\frac{3}{4}". Then probability that the student answers 10 questions incorrectly is "(\\frac{3}{4})^{10}\\approx 0.056" (events "the student answers the 1_st question, the 2_nd question,"\\ldots", the 10_th question incorrectly" are independent collectively).
b) We should find probability that the student answers 8, 9 or 10 questions correctly. So probability is "\\sum_{k=8}^{10}C_{10}^k(\\frac{1}{4})^k(\\frac{3}{4})^{10-k}\\approx 0.000416" (Bernoulli's formula).
c) We should find probability the the student answers 6, 7, 8, 9 or 10 questions correctly.
So probability is "\\sum_{k=6}^{10}C_{10}^k(\\frac{1}{4})^k(\\frac{3}{4})^{10-k}\\approx 0.0197" (Bernoulli's formula).
Comments
Leave a comment