Question #106383
1000 caterpillars are divided at random into 2 lots of 500 caterpillars each. Then one lot is sprayed with zap and the other lot with zoom. Of those sprayed with zap, 400 caterpillars were killed, and those sprayed with zoom , 450 were killed. Suppose a caterpillar is selected at random, what is the probability that it was sprayed with zap. B) what is the probability that it was killed? C) what is the probability that it was killed given it was sprayed with zap, d( are the events zap and killed independent
1
Expert's answer
2020-03-24T17:35:27-0400

let events as,

K=killed caterpillarsZ1=sprayed with zapZ2=sprayed with zoomK=killed\ caterpillars\\ Z_1=sprayed \ with\ zap\\ Z_2=sprayed\ with\ zoom\\


a)  The probability that caterpillar was sprayed with zap,

P(Z1)=Zap sprayed caterpillarsAll caterpillarsP(Z1)=5001000P(Z1)=0.5P(Z_1)=\frac{Zap\ sprayed\ caterpillars}{All\ caterpillars}\\ P(Z_1)=\frac{500}{1000}\\ P(Z_1)=0.5\\


b) The probability that caterpillar was killed,

P(K)=All killed caterpillarsAll caterpillarsP(K)=8501000P(K)=0.85P(K)=\frac{All\ killed\ caterpillars}{All\ caterpillars}\\ P(K)=\frac{850}{1000}\\ P(K)=0.85\\


c) The probability that caterpillar was killed given it was sprayed with zap

P(KZ1)=number of sampes(KZ1)number of samples event(Z1)P(KZ1)=400500P(KZ1)=0.8P(K|Z_1)=\frac{number \ of\ sampes(K\cap Z_1)}{number \ of\ samples\ event(Z_1)}\\ P(K|Z_1)=\frac{400}{500}\\ P(K|Z_1)=0.8


d) The Killed event and Zap event is dependent. Because

P(KZ1)P(K)P(K|Z_1) \not = P(K) according to part (b) & (c)


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