This is the binomial distribution with p=0.3,n=5.
a) P(X=0)=C550.30(1−0.3)5=0.1681.
b) P(X=2)=C520.32(1−0.3)3=0.3087.
c) P(X≥3)=P(X=3)+P(X=4)+P(X=5)=C530.33(1−0.3)2+
+C540.34(1−0.3)1+C550.35(1−0.3)0=0.1638.
d) P(X=5∗0.2)=P(X=1)=C510.31(1−0.3)4=0.3602.
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