This is the binomial distribution with "p=0.3, \\;\\;n=5."
a) "P(X=0)=C_5^50.3^0(1-0.3)^5=0.1681."
b) "P(X=2)=C^2_50.3^2(1-0.3)^3=0.3087."
c) "P(X\\ge3)=P(X=3)+P(X=4)+P(X=5)=C^3_50.3^3(1-0.3)^2+"
"+C^4_50.3^4(1-0.3)^1+C^5_50.3^5(1-0.3)^0=0.1638."
d) "P(X=5*0.2)=P(X=1)=C^1_50.3^1(1-0.3)^4=0.3602."
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