Answer to Question #113343 in Real Analysis for Awais

Question #113343
Find limit of sequence =n+2/3-n
1
Expert's answer
2020-05-03T17:31:55-0400

Let (xn)=n+23n(x_n)=\frac{n+2}{3-n} be a sequence in R\R .

limn(xn)=limnn+23n\therefore \lim_{n\to \infin} (x_n)=lim_{n\to \infin} \frac{n+2}{3-n}

Divided numerator and denominator by n. We get


limn(xn)=limn1+2n3n1lim_{n\to \infin}(x_n)=lim_{n\to \infin} \frac{1+\frac{2}{n}}{\frac{3}{n}-1}

=11=1=\frac{1}{-1}=-1



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