Let (xn)=n+23−n(x_n)=\frac{n+2}{3-n}(xn)=3−nn+2 be a sequence in R\RR .
∴limn→∞(xn)=limn→∞n+23−n\therefore \lim_{n\to \infin} (x_n)=lim_{n\to \infin} \frac{n+2}{3-n}∴limn→∞(xn)=limn→∞3−nn+2
Divided numerator and denominator by n. We get
=1−1=−1=\frac{1}{-1}=-1=−11=−1
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