Since X = {xn} n=1,2,.. is convergent< we obtain that there exists A = . So, for every >0 there exists such N0, that for every n>N0 the following is true: |xn - A|< . (1)
We obtain the same for X+Y = {xn + yn}, n = 1,2,.. and B = :
for every there exists such N1, that for every n>N1 the following is true:
|xn + yn - B|<
Let us now denote with N = max{N0, N1}. Let's show that Y is convergent with the following limit:
B-A = . For this, let's check the definition:
We will prove that for every there exists such N2, that for every n>N2 the following is true:
|yn - (B-A)|< (the definition of the limit): (assuming n>N (1) and (2) are both true)
|yn - (B-A)| = |(xn - A) - (xn + yn - B)| |xn - A| + |xn + yn - B| . So for n>N this is true.
Exactly what we needed to show.
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