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Quantitative Methods
Use n=6 subdivision to approximate the value of
∫_0^6▒√(x+2) dx by the trapezoidal rule
∫_0^6▒√(x+2) dx by the trapezoidal rule
Quantitative Methods
Find the root of the equation tanx + tanhx = 0 which lies in the interval (1.6, 3.0) correct to four significant digits using the method of false position.
Quantitative Methods
find the roots using newton rhapson. Stop until at 15th iteration or when approximate percent relative error is below 0.05%.
2x^5+x^4-2x-1=0
2x^5+x^4-2x-1=0
Quantitative Methods
find the roots using simple fixed point iteration. Stop until at 15th iteration or when approximate percent relative error is below 0.05%.
3x^4-8x^3-37x^2+2x+40
3x^4-8x^3-37x^2+2x+40
Quantitative Methods
find the roots using simple fixed point iteration. Stop until at 15th iteration or when approximate percent relative error is below 0.05%.
e^x+x=4
e^x+x=4
Quantitative Methods
Hi, I’m a finance students and I have a Big problem with The use of VBA programming on excel can you help me please I have an exam on monday
Quantitative Methods
1- use bisection method to find out the positive sequare root of 30 correct to 4 decimal places.
2- solve by iteration method
(1) 1+log x =x/2
(2) Sin x = x+1/x-1
(3) X^3 - 2x^2 - 5 =0
3- Find the smallest root of the equation
1 - x + x^2/(2!)^2 - x^3/(3!)^2 + x^4/(4!)^2 - x^5/(5!)^2 + .................. = 0
2- solve by iteration method
(1) 1+log x =x/2
(2) Sin x = x+1/x-1
(3) X^3 - 2x^2 - 5 =0
3- Find the smallest root of the equation
1 - x + x^2/(2!)^2 - x^3/(3!)^2 + x^4/(4!)^2 - x^5/(5!)^2 + .................. = 0
Quantitative Methods
find the smallest positive in which lies the following tanx+tanhx=0
Quantitative Methods
Solve the differential equation dy/dx=(x-y)/(x+y),with y(0)=1 numerically for x=0.1 by Eular's method(five step)
Quantitative Methods
To approximate the value of f'''(xk), the following formulas are used
f'''k =1/h^3[ fk+3 −3 fk+2 +3 fk+1 − fk]
f'''k =1/2h3[ fk+2 −2 fk+1 +2 fk−1 − fk−2]
Which formula do you find more accurate, and why?
f'''k =1/h^3[ fk+3 −3 fk+2 +3 fk+1 − fk]
f'''k =1/2h3[ fk+2 −2 fk+1 +2 fk−1 − fk−2]
Which formula do you find more accurate, and why?
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#340153 on Dec 2023
#340153 on Dec 2023