Prove that 2n+1 > (n + 2) · sin(n) for all positive integers n.
"2n+1>n+2" for "n>1."
Since "|sin(n)|\\le1", "2n+1>(n+2)sin(n)" for "n>1."
For n=1, "sin(1)<1," and "3>3*sin(1)".
Therefore, 2n+1 > (n + 2) · sin(n) for all positive integers n.
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