Prove that 2n+1 > (n + 2) · sin(n) for all positive integers n.
2n+1>n+22n+1>n+22n+1>n+2 for n>1.n>1.n>1.
Since ∣sin(n)∣≤1|sin(n)|\le1∣sin(n)∣≤1, 2n+1>(n+2)sin(n)2n+1>(n+2)sin(n)2n+1>(n+2)sin(n) for n>1.n>1.n>1.
For n=1, sin(1)<1,sin(1)<1,sin(1)<1, and 3>3∗sin(1)3>3*sin(1)3>3∗sin(1).
Therefore, 2n+1 > (n + 2) · sin(n) for all positive integers n.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments