Question #223957

Prove that 2n+1 > (n + 2) · sin(n) for all positive integers n.


1
Expert's answer
2021-08-09T09:20:16-0400

2n+1>n+22n+1>n+2 for n>1.n>1.

Since sin(n)1|sin(n)|\le1, 2n+1>(n+2)sin(n)2n+1>(n+2)sin(n) for n>1.n>1.

For n=1, sin(1)<1,sin(1)<1, and 3>3sin(1)3>3*sin(1).

Therefore, 2n+1 > (n + 2) · sin(n) for all positive integers n.



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