Find the inverse of matrix A given below using the formula A -1 =CT/│A│
A=∣−6−4−4−1−46 −65−1∣\begin{vmatrix} -6 & -4 & -4 \\ -1 & -4 & 6 \\\ -6 & 5 & -1 \end{vmatrix}∣∣−6−1 −6−4−45−46−1∣∣
At first step we compute the determinant of AAA: ∣A∣=(−6)(−4)(−1)+(−1)(−4)5+(−4)(−6)6−(−6) 6 5+(−1)(−4)+6(−4)(−4)=−24+20+144+180+4+96=420|A|=(-6)(-4)(-1)+(-1)(-4)5+(-4)(-6)6-(-6)\,6\,5+(-1)(-4)+6(-4)(-4)=-24+20+144+180+4+96=420∣A∣=(−6)(−4)(−1)+(−1)(−4)5+(−4)(−6)6−(−6)65+(−1)(−4)+6(−4)(−4)=−24+20+144+180+4+96=420
Matrix C⊤=(−26−24−40−37−1840−295420)C^{\top}=\left(\begin{array}{lll}-26&-24&-40\\-37&-18&40\\-{29}&54&20\end{array}\right)C⊤=⎝⎛−26−37−29−24−1854−404020⎠⎞has the form: Matrix A⊤A^{\top}A⊤ has the form: A=(−13210−235−221−37420−370221−29420970121)A=\left(\begin{array}{lll}-\frac{13}{210}&-\frac{2}{35}&-\frac{2}{21}\\-\frac{37}{420}&-\frac{3}{70}&\frac{2}{21}\\-\frac{29}{420}&\frac{9}{70}&\frac{1}{21}\end{array}\right)A=⎝⎛−21013−42037−42029−352−703709−212212211⎠⎞.
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