Question #265978

Let V = R3 and let W = {(x, y, z)  R3| z = x + y}. Prove that W is a subspace of V.


1
Expert's answer
2021-11-15T16:28:19-0500


Let V is a linear space and WVW\subset V is some subset of V. W is a linear subspace in V iff:

  1. (v1,v2W)(v1+v2VW;\forall(v_1,v_2\in W)(v_1+v_2\in VW;
  2. (cR,vW)(cvW);\forall(c\in R,v\in W)(c\cdot v\in W);

We must verify these two properties.

  1. Let v1=(x1,y1,z1),v2=(x2,y2,z2)Wv_1=(x_1,y_1,z_1) ,v_2=(x_2,y_2,z_2)\in W . It is means that z1=x1+y1, z2=x2+y2z_1=x_1+y_1, \space z_2=x_2+y_2 . Then v1+v2=(x1+x2,y1+y2,z1+z2)V=R3v_1+v_2=(x_1+x_2,y_1+y_2,z_1+z_2)\in V=R^3 be definition of R3R^3 and because of z1+z2=(x1+y1)+(x2+y2)=(x1+x2)+(y1+y2)z_1+z_2=(x_1+y_1)+(x_2+y_2)=(x_1+x_2)+(y_1+y_2) we have that v1+v2Wv_1+v_2\in W , first condition takes place.
  2. Let v=(x,y,z)W,cRv=(x,y,z) \in W, c\in R . It is means that z=x+y. Value cv=c(x,y,z)=(cx,cy,cz)V=R3c\cdot v=c\cdot(x,y,z)=(cx,cy,cz)\in V=R^3

by definition? to verify that cvWcv\in W we see that cz=c(x+y)=cx+cyc\cdot z=c\cdot(x+y)=c\cdot x+c\cdot y and this means that the second property is proved also.

Thus we have proved that W is a linear subspace.


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