Question #203162

Prove that there does not exist a linear map T : R5 ! R5

such that range T = null T.


1
Expert's answer
2021-07-12T16:21:01-0400

By the rank-nullity theorem we have dimImT+dimkerT=dimR5=5\dim\operatorname{Im}T+\dim\ker T=\dim\mathbb R^5=5

If ImT=kerT\operatorname{Im}T=\ker T, then dimImT=dimkerT=52\dim\operatorname{Im}T=\dim\ker T=\frac{5}{2}. It is impossible, so ImTkerT\operatorname{Im}T\neq\ker T


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