Question #203158

Suppose S; T 2 L(V ) are such that ST = T S. Prove that null S is invariant under T.



Expert's answer

We need to prove T(null⁡S)⊂null⁡ST(\operatorname{null}S)\subset\operatorname{null}S

Take arbitrary x∈T(null⁡S)x\in T(\operatorname{null}S)

Since x∈T(null⁡S)x\in T(\operatorname{null}S), there exists y∈null⁡Sy\in\operatorname{null}S such that x=Tyx=Ty

Then Sx=STySx=STy. Since ST=TSST=TS, we have Sx=TSySx=TSy

Sy=0Sy=0, because y∈null⁡Sy\in\operatorname{null}S, then Sx=TSy=T0=0Sx=TSy=T0=0, that is x∈null⁡Sx\in\operatorname{null}S.

Since we take arbitrary x∈T(null⁡S)x\in T(\operatorname{null}S), we have T(null⁡S)⊂null⁡ST(\operatorname{null}S)\subset\operatorname{null}S


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